Question

Hello guys can someone help me with this, my dead line is too close hehe

Answer 1

We will solve all the questions by pythagoras theorem i.e.

`\boxed{ \mathcal{ {H}^(2) = {P}^(2) + {B}^(2) }}`

#1

`\green \implies \red{ \sf{30}^(2) = {x}^(2) + {18}^(2) }`

`\green \implies \red{ \sf{x}^(2) = {30}^(2) - {18}^(2) }`

`\green \implies \red{ \sf{x}^(2) = 900 - 324 }`

`\green \implies \red{ \sf{x}^(2) = 900 - 324 }`

`\green \implies \red{ \sf{x}^(2) = 576}`

`\green \implies \red{ \sf \: x= √(576)}`

`\green \implies \red{ \sf \: x= 24}`

#2

`\orange \implies \blue{ \sf \: {14}^(2) = {x}^(2) + {x}^(2) }`

`\orange \implies \blue{ \sf \: {14}^(2) = 2{x}^(2) }`

`\orange \implies \blue{ \sf \: 196= 2{x}^(2) }`

`\orange \implies \blue{ \sf \: 98 = {x}^(2) }`

`\orange \implies \blue{ \sf √(98 )= {x}}`

`\orange \implies \blue{ \sf x = 9.9}`

#3

`\pink \implies \purple{ \sf {x}^(2) = {70}^(2) + {240}^(2) }`

`\pink \implies \purple{ \sf {x}^(2) = 4900 + 57600 }`

`\pink \implies \purple{ \sf {x}^(2) = 62500 }`

`\pink \implies \purple{ \sf x = √(62500) }`

`\pink \implies \purple{ \sf x = 250 }`