Question

Hello guys can someone help me with this, my dead line is too close hehe

Answer 1

We are given the measurements:

• AE = 8m-13
• PX = 5m+20

Now,

`\boxed { \mathcal{ \green{AE = PX}}}`

Since, the diagonals of a rectangle are equal..

• Put the values of AE and PX equal to find m

`\pink \implies \purple { \sf8m -13 = 5m + 20 }`

`\pink \implies \purple { \sf8m -13 - 5x = 20 }`

`\pink \implies \purple { \sf8m - 5m = 20 + 13 }`

`\pink \implies \purple { \sf3m = 33 }`

`\boxed{ \mathfrak { \red{m = 11}}}`

#4

`\blue \longmapsto \orange{ \tt \: AE = 8m - 13}`

`\blue \longmapsto \orange{ \tt \: AE = 8(11) - 13}`

`\blue \longmapsto \orange{ \tt \: AE = 88- 13}`

`\boxed{ \mathfrak{ \red{AE = 75 \: cm}}}`

#5

`\blue \longmapsto \orange{ \tt \:PX = 5m+ 20}`

`\blue \longmapsto \orange{ \tt \:PX = 5(11)+ 20}`

`\blue \longmapsto \orange{ \tt \:PX = 55+ 20}`

`\boxed{ \mathfrak{ \red{ PX= 75 \: cm}}}`

#6

`\boxed{ \mathfrak { \red{m = 11}}}`