Question

PLEASE HELP QUICK!!! Find a cubic polynomial equation with real coefficients that has the given numbers as roots.

-5 and 1 - i​

Answer 1

Below

Explanation:

Imaginary roots always come in pairs ...if 1- i is a root then 1+i is a root

(x+5)(x-1+i)(x-1-i) = 0 Expand and simplify to:

x^3 + 3x^2 -8x + 10 =0