Answer:
GG and Gg.
Step-by-step explanation:
Based on the information provided, we can infer that one parent must have been homozygous dominant (GG) for seed color, while the other parent must have been heterozygous (Gg).
Let's use Punnett squares to demonstrate this:
Punnett square for the homozygous dominant parent (GG):
G G
G GG GG
G GG GG
Punnett square for the heterozygous parent (Gg):
G g
G GG Gg
G GG Gg
From the above Punnett squares, we can see that when a homozygous dominant parent (GG) is crossed with a heterozygous parent (Gg), all the offspring will have a genotype of Gg, and all will have green seeds. Therefore, this cross cannot produce the observed 25% green-seeded plants.
However, if we assume that the heterozygous parent was actually Gg, then we can explain the observed data. In this case, the Punnett square for the cross between two heterozygous parents would look like this:
G g
G GG Gg
g Gg gg
From this Punnett square, we can see that 25% of the offspring will have a genotype of gg, which is homozygous recessive for seed color and produces green seeds. Therefore, the genotypes of the parents are GG and Gg.