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What is the center of a circle whose equation is x2 + y2 – 12x – 2y + 12 = 0? A.) (–12, –2) B.) (–6, –1) C.) (6, 1) D.) (12, 2)

What is the center of a circle whose equation is x2 + y2 – 12x – 2y + 12 = 0? A.) (–12, –2) B.) (–6, –1) C.) (6, 1) D.) (12, 2)
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What is the center of a circle whose equation is x2 + y2 – 12x – 2y + 12 = 0?

A.) (–12, –2)
B.) (–6, –1)
C.) (6, 1)
D.) (12, 2)

asked
User Rajneesh
by
7.7k points

1 Answer

5 votes
Answer is going to be letter C.) (6,1)
answered
User Jdruwe
by
8.8k points
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