Question

A bag of M&M's has 5 red, 2 green, 6 blue, and 3 yellow M&M's. What is the probability of randomly picking a yellow?

Answer 1

Answer:
`(3)/(16)` or 18.75%

Explanation:

We will divide wanted outcomes by total possible outcomes.

`\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{\text{picking a yellow M\&M}}{\text{number of M\&M's in the bag}} =(3)/(5+2+6+3) =(3)/(16)`