Question

6 What is the molarity, in M to the nearest tenth, of a solution that contains 30 grams

of NaOH in 500 milliliters of solution?
Record your answer and fill in the bubbles on your answer document. Be sure to us
the correct place value.

Answer 1

Explanation:

molar mass of NaOH = 23 g/mol (for Na) + 16 g/mol (for O) + 1 g/mol (for H) = 40 g/mol

moles of NaOH = 30 g / 40 g/mol = 0.75 mol

500 mL = 0.5 L

molarity = moles of solute / liters of solution

molarity = 0.75 mol / 0.5 L = 1.5 M

Therefore, the molarity of the solution is 1.5 M to the nearest tenth.