Question

An arithmetic sequence starts at 0 and each successive number equals the previous number plus 6. Thus a1=0 and the distance d=6 What is the sum of the first 36 terms?

Answer 1

228

Explanation:

sum of the first n term = (n/2) [ 2a +(n-1)d]

sum of the first 36 terms =(36/2)[ 2×0+ (36-1)6]

= 228