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What are the foci of the graph x^2/40-y^2/81=1

What are the foci of the graph x^2/40-y^2/81=1
asked 7.4k views
2 votes
What are the foci of the graph x^2/40-y^2/81=1

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User Xavier Delamotte
by
8.1k points

2 Answers

6 votes

Answer: y21600x281=1 y 2 1600 - x 2

Step-by-step explanation: for sure chfjjgffjfj ;)

answered
User Michael Berdyshev
by
8.9k points
5 votes

Answer:

Explanation:

(y^2)/1600-(x^2)/81=1. y21600−x281=1 y 2 1600 - x 2

answered
User Etov
by
7.7k points
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