Question

Solve for vertex algebraically -x^2-6x-5

Answer 1

The vertex is located at (3,22)

Answer 2

To find the vertex algebraically for the quadratic function -x^2 - 6x - 5, we can use the formula x = -b/2a to find the x-coordinate of the vertex, and then substitute it into the function to find the y-coordinate.

Here, a = -1 and b = -6, so x = -(-6)/(2*(-1)) = 3. Substituting x = 3 into the function, we get:

-y = -(3)^2 - 6(3) - 5 = -22

y = 22

Therefore, the vertex is at (3, 22).