Question

Find the vertex of the parabola y=x^2-1

Answer 1

`\textit{vertex of a vertical parabola, using coefficients} \\\\ y=x^2-1\implies y=\stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{+0}x\stackrel{\stackrel{c}{\downarrow }}{-1} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{ 0}{2(1)}~~~~ ,~~~~ -1-\cfrac{ (0)^2}{4(1)}\right) \implies \left( - \cfrac{ 0 }{ 2 }~~,~~-1 - \cfrac{ 0 }{ 4 } \right) \\\\\\ \left( 0 ~~~~ ,~~~~ -1 +0 \right)\implies (0~~,~-1)`