A 4.0-N puck is travelling at 3.0m/s. It strikes an 8.0-N puck, which is stationary. The two pucks stick together. Their common final speed is:

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asked Apr 15, 2024 89.7k views

1 Answer

Sharmeca · Answer 1 · 2024-04-21T01:27:22+0000

Answer: 2.858(m/s)

Explanation: F= mg→ m1= 4.0/9.8 = 0.408(kg)

m2= 8 /9.8 = 0.816(kg)

m1v1 = (m1+m2)v2→ v2= m1v1(m1+m2) = 0.408+3/(0.408+0.816)= 2.8589m/s)