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An 11 M solution containing 449. 4 g of ammonium sulfate would contain how many liters?

1 Answer

1 vote

Answer:

309.1 mL

What is molarity?

The most common way to express solution concentration is molarity (M), which is defined as the amount of solute in moles divided by the volume of solution in litres: M = moles of solute/litres of solution.

To calculate volume required for the solution, we first must find number of moles (n) required. To do this, we can divide mass in grams, by molar mass. Molar mass can be found on a standard IUPAC Periodic Table (International Union of Pure and Applied Science).

n[(NH₄)₂SO₄] = m/MM = 449.4/[(14.01+1.008×4)×2+32.07+16.00×4]

= 3.4006 mol

Now we have moles of solute, as well as molarity, (from the question - 11M) Thus, we can calculate litres of solution.

Volume = moles ÷ molarity = 3.4006 / 11 = 0.309 L = 309.1 mL

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User DarkZeros
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