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How many grams of F are in 295 g CaF2?

asked
User Doni
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1 Answer

5 votes
M (Ca) = 40.1
M (2 F) = 38.0
M = 78.1
%F = 38/78.1
%F = 48.7
m(F) = 0.487 * 415 = 202.1

Answer: 202.1
answered
User Larrys
by
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