Question

√(6-(-1)² + (-2-(-1)²​

Answer 1

To evaluate the expression √(6-(-1)² + (-2-(-1)²), we need to follow the order of operations, which is Parentheses, Exponents, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right).

1. First, we need to evaluate the expressions inside the parentheses:

-1² = (-1) × (-1) = 1

-2-(-1)² = -2-1 = -3

2. Next, we substitute these values into the expression:

√(6-(-1)² + (-2-(-1)²)

= √(6-1 + (-2-1))

= √(5 - 3)

= √2

Therefore, the value of the expression √(6-(-1)² + (-2-(-1)²) is √2.

Explanation:

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Answer 2

To simplify this expression, we need to first evaluate the terms inside the square root:

(-1)² = 1

(-2 - (-1))² = (-2 + 1)² = (-1)² = 1

Now we can substitute these values and simplify the expression:

√(6 - (-1)² + (-2 - (-1))²)

= √(6 - 1 + 1)

= √6

Therefore, the simplified form of the expression is √6.