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In the given equation, b is a positive constant. The sum of the solutions of the equation is 5. What is the value of b? x²(x+3)(x - b) = 0

In the given equation, b is a positive constant. The sum of the solutions of the equation is 5. What is the value of b? x²(x+3)(x - b) = 0
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In the given equation, b is a positive constant.

The sum of the solutions of the equation is 5.
What is the value of b?
x²(x+3)(x - b) = 0

asked
User Bill Greer
by
8.4k points

1 Answer

5 votes

Answer:

0

Explanation:

X^2(x+3)(x-b)=0x2 = 0x =√0x= 0

(hope this helps you <:)

answered
User NunoCarmo
by
8.3k points
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