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Factorise : 9x^{2} +4x^{2} +16z^{2} +12xy-16yz-24xz[/tex]

1 Answer

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To factorize the expression 9x^2 + 4x^2 + 16z^2 + 12xy - 16yz - 24xz, we can group the terms with common factors:

(9x^2 + 4x^2) + (16z^2 - 16yz) + (12xy - 24xz)

Factor out the common factors from each group:

9x^2 + 4x^2 = 13x^2

16z^2 - 16yz = 16z(z - y)

12xy - 24xz = 12x(y - 2z)

Putting it all together, we have:

9x^2 + 4x^2 + 16z^2 + 12xy - 16yz - 24xz = 13x^2 + 16z(z - y) + 12x(y - 2z)

Therefore, 9x^2 + 4x^2 + 16z^2 + 12xy - 16yz - 24xz can be factorized as (13x^2 + 16z(z - y) + 12x(y - 2z)).

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