How is the series 3+5+7+...+51 represented in sigma notation?

Question

asked Sep 10, 2024 211k views

2 Answers

Mpettis · Answer 1 · 2024-09-14T11:54:01+0000

Answer:

The third one

Explanation:

The only one which gives the last number of the sequence is the third one as subbing in 16 you get 3×16 + 3 = 48 + 3 = 51