Question

Find the Perimeter of the figure below, composed of an isoceles trapezoid and one semicircle. Rounded to the nearest tenths place

Answer 1

52.4

Explanation:

The perimeter of a Trapezoid:

P=a+b+c

6+15+8+8=37

The perimeter of a semicircle:

`L=\pi r+d= 3\pi+6\\=15.4248 \\=15.4`

Add both together:

37+15.7=52.4

Answer 2

27.3

Explanation:

Here, we can add the outside sides of the trapezoid, which are already given:

6 + 6 + 9 = 21

Then for the circle, we can find half of the circumference with πr. The diameter of the circle is 4 (given), so the radius (half the diameter) is 2.

Thus,

π(2) ≈ 6.28

By adding all of these parts, you get

21 + 6.28 = 27.28

Which, rounded to the tenths is 27.3