Answer:
![[M^(-1) L^(3) T^(-2)]](https://img.qammunity.org/2024/formulas/physics/high-school/e1sdk5teyb2o5gzis5pj5ms5px3wceic42.png)
Step-by-step explanation:
From Newton’s law of gravitation,
Force (F) = [GmM] × 
 
Gravitational Constant (G) = F × 
 × 
 . . . . (1)
Since, Force (F) = Mass × Acceleration = M × 
![[LT^(-2)]](https://img.qammunity.org/2024/formulas/physics/high-school/2jmrk8njvj7qaz9jk2xtpw6wfelciizaph.png)
∴ The dimensional formula of force = 
 . . . . (2)
On substituting equation (2) in equation (1) we get,
Gravitational Constant (G) = F × 
× 
![[Mm]^(-1)](https://img.qammunity.org/2024/formulas/physics/high-school/76xp9jawdgum0icd6wuz82utas1jku0fbl.png)
Or, G = 
 × 
× 
= [
]
Therefore, the gravitational constant is dimensionally represented as 
