Question

7. Applying Concepts A 500-N student stands

on one foot. A 750-N student stands on two
feet. If both students wear the same size shoe,
which exerts the greater pressure?

-someone please helppp

Answer 1

First student

Explanation:

P = F/A

F1 = 500N

F2 = 750N

First student is standing on one foot, which is the area in contact, so this we can call A1.

Second student is standing on two feet, because they both wear same size shoes, we can assume the area of contact per foot is the same. Because the second student is on two feet, A2 is double A1.

To make it simpler we can say:
A1 = 1

A2 = 2

Plug values into P=F/A eqn.

P1 = 500/1 = 500 Pa

P2 = 750/2 = 375 Pa

500 > 375, therefore the first student exerts greater pressure.