Question

How many grams Mn2O3 would be produced from the complete reaction of MnO2?

Zn + 2MnO2 + H2O --> Zn(OH)2 + Mn2O3

Mno2 : 86.94 g/mol
Mn2O3 : 157.88 g/mol [?] g Mn2O3

Answer 1

To calculate the number of grams of Mn2O3 produced from the complete reaction of MnO2, you need to use the balanced chemical equation and the molar masses of MnO2 and Mn2O3.

Step-by-step explanation:

To find the number of grams of Mn2O3 produced from the complete reaction of MnO2, we need to use the balanced chemical equation and the molar masses of MnO2 and Mn2O3.

The balanced equation is:

Zn + 2MnO2 + H2O → Zn(OH)2 + Mn2O3

From the equation, we can see that 2 moles of MnO2 react to produce 1 mole of Mn2O3. Therefore, the molar ratio is 2:1.

To calculate the number of grams of Mn2O3 produced, we can use the following calculation:

(molar mass of Mn2O3) × (moles of MnO2 consumed)

Using the molar masses given: (157.88 g/mol) × (moles of MnO2)