Question

The father is 3 times age as his son. After 15 years he is twice age as his son what are their present ages

Answer 1

Explanation:

Let the present age of son be x years

Then, present age of other =3x years

After 15 years :

Son's age =(x+15) years

Father's age =(3x+15) years

But, according to the question.

⇒(3x+15)=2(x+15)

⇒3x+15=2x+30

⇒3x−2x=30−15

⇒x=15

∴ Son's age is 15 years.