Solve for x : (can be a complex number) {x}^(2) = - 16 ​

Question

Solve for x : (can be a complex number)


`{x}^(2) = - 16`
​

Answer 1

Explanation:

The solution to this equation would be x = ±4i, where i is the imaginary unit, defined as the square root of -1.

Answer 2

Explanation:

We have the equation:

x^2 = -16

Taking the square root of both sides, we get:

x = ± √(-16)

Now, the square root of a negative number is not a real number, but it can be expressed as a complex number using the imaginary unit i, where i^2 = -1.

So, we can write:

√(-16) = √(16) × √(-1) = 4i

Therefore, the solutions to the equation are:

x = ± 4i

So, the answer is x = 4i or x = -4i.