Answer:
x = 1 + (1/2)i√2 and x = 1 - (1/2)i√2
Explanation:
To solve the quadratic equation 2x^2 - 4x + 3 = 0, we can use the quadratic formula:
x = (-b ± sqrt(b^2 - 4ac)) / 2a
where a = 2, b = -4, and c = 3.
Substituting these values, we get:
x = (-(-4) ± sqrt((-4)^2 - 4(2)(3))) / (2(2))
= (4 ± sqrt(16 - 24)) / 4
= (4 ± sqrt(-8)) / 4
= (4 ± 2i√2) / 4
= 1 ± (1/2)i√2
Therefore, the solutions of the quadratic equation 2x^2 - 4x + 3 = 0 are x = 1 + (1/2)i√2 and x = 1 - (1/2)i√2.