Question

najib cuts out a rectangle that has a perimeter of 50 inches and a length of 17 inches. he cuts out another rectangle that is the same length and twice as wide.

Answer 1

66 inches

Explanation:

perimeter = 2(l+b)

here, perimeter is 50 and length is 17

let the width be x,

=> 50 = 2(17+x)

=> 50 = (2*17)+(2*x)

=> 50 = 34 + 2x

=> 50 - 34 = 2x [transposing method]

=> 16 = 2x

=> 16/2 = x

=> 8 = x

8 inches = width of the first triangle

we know, the other rectangle's length is 17

and it is said that the width is twice the width of the first triangle

so the length = 17, width = 2*8 = 16

for the perimeter

p = 2(l+b),

=> p = 2(17+16)

=> p = (2*17)+(2*16)

=> p = 34+32

=> p = 66

so the perimeter of the other rectangle is 66