Question

Please help me. I am lost.
Rewrite 2sinx-cos^2x-2 using only one trig function.

Answer 1

Answer:(sinx+1)^2-4

Explanation:

2sinx-cos^2x-2 =2sinx-(1-sin^2x)-2=2sinx-1+sin^2x-2=2sinx+sin^2x-3=(sinx+1)^2-4