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Solve the system algebraically. Check your work. 5x + 2y = 10 3x + 2y = 6​

1 Answer

4 votes

Answer:

x = 2

y = 0

Explanation:

The two equations are

5x + 2y = 10 [1]

3x + 2y = 6 [2]

Notice the y coefficients are the same in both equations

[1] - [2] will eliminate the y terms and let you solve for x

[1] - [2] :

5x + 2y - (3x + 2y) = 10 -6

==> 5x +2y -3x - 2y = 4

==> 2x + 0 = 4

==> 2x = 4

x = 4/2

x = 2

Plug this value of x into equation [1]:
5(2) + 2y = 10
10 + 2y = 10

Subtract 10 both sides

10 - 10 + 2y = 10 - 10

2y = 0

y = 0

We can check our work by substituting for x and y in equation [2] left side
3x + 2y = 3(2) + 2(0) = 6 - 0 = 6 which is consistent with the right side

answered
User SaravInfern
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