Question

3

Translate the problem into an equation and then use your equation to answer the
question.
Alex could arrive on time for his appointment if he leaves now and drives 50 mph.
However, Alex leaves the house 15 minutes earlier, drives 40 mph, and arrives on
time. How far from Alex's house is the appointment?

Answer 1

We can use the following equation to answer the question: d = (50 mph)(15 minutes/60 minutes) + (40 mph)(t minutes/60 minutes).

Where t is the total time it takes Alex to travel to the appointment. Solving for t, we get t = (d - 15 mph)/(10 mph).

Therefore, the appointment is d = (50 mph)(15 minutes/60 minutes) + (40 mph)(t minutes/60 minutes) = (750 miles/hr)t miles away from Alex's house.