Question

Select the two values of x that are roots of this equation.

x^2+3x-5=0

Answer 1

Option:-

• 
  `{ \rm \bold{{A ) x = ( - 3 + √(29) )/(2) }}}`

`\:`

• 
  `{ \rm{ \bold{C )x = ( - 3 - √(29) )/(2) }}}`

`\:`

━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Given:-

• 
  `\rm {x}^(2) + 3x - 5 = 0`

`\:`

By using quadratic equation formula:-

• 
  `\rm \bold{{a {x}^(2) + bx + c = 0 }}`

`\:`

Formula:-

• 
  `\boxed{ \rm{ \red{x = \frac{ - b \pm \sqrt{ {b}^(2) - 4ac} }{2a} }}}`

`\:`

Solution:-

• 
  `\boxed{ \underline{ \rm \bold{\: a = 1, b = 3 , c = -5 }}}`

`\:`

• 
  `\rm{ \bold{x = \frac{ - b \pm\sqrt{ {b }^(2) - 4ac } }{2a}} }`

`\:`

• 
  `\rm \: x \: \frac{ - 3 + \sqrt{ {(3)}^(2) - 4 * 1 * ( - 5) } }{2 * 1}`

`\:`

• 
  `\rm \: x \: ( - 3 + √( 9- 4 * ( - 5) ) )/(2 )`

`\:`

• 
  `\rm \:x = ( - 3 + √(9 - ( - 20)) )/(2)`

`\:`

• 
  `\underline{\boxed{ \green{ \rm \bold{ \: x = ( - 3 + √(29) )/(2) }}}}`

`\:`

and ,

• 
  `\rm \: x \: \frac{ - 3 - \sqrt{ {(3)}^(2) - 4 * 1 * ( - 5) } }{2 * 1}`

`\:`

• 
  `\rm \: x \: ( - 3 - √( 9- 4 * ( - 5) ) )/(2 )`

`\:`

• 
  `\rm{x = ( - 3 - √(9 - ( - 20)) )/(2) }`

`\:`

• 
  `\underline{ \boxed{ \rm{ \bold{\color{green}x = ( - 3 - √(29) )/(2) }}}}`

`\:`

hope it helps! :)