Answer:
Let's say the number of sweets that Amol has is A.
According to the problem, the number of sweets that Gemma has is 6 times the number of sweets that Amol has. Therefore, Gemma has 6A sweets.
The number of sweets that Harry has is half the number of sweets that Gemma has. Therefore, Harry has 1/2 * 6A = 3A sweets.
So the ratio of the number of sweets that Amol, Gemma, and Harry have respectively is:
A : 6A : 3A
Simplifying this ratio by dividing each term by A, we get:
1 : 6 : 3
Therefore, the ratio of the number of sweets that Amol has to the number of sweets that Gemma has to the number of sweets that Harry has is 1:6:3