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The area of a rectangle is 56 cm^2. The length is 2 cm more than x and the width is 5 cm less than twice x. Solve for x. Round to the nearest whole number

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User Edwar
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1 Answer

3 votes

Answer: x = 26 cm.

Explanation:

Let x = the length of the rectangle

The area of a rectangle is the length times the width, so we can set up the equation:

56 cm^2 = x(2x - 5)

Expand the parentheses and solve for x:

56 cm^2 = 2x^2 - 5x

Add 5x to both sides:

2x^2 + 5x = 56 cm^2 + 5x

Subtract 56 cm^2 from both sides:

2x^2 = 5x + 56 cm^2

Divide both sides by 2:

x^2 = 5x/2 + 28 cm^2

Subtract 5x/2 from both sides:

x^2 - 5x/2 = 28 cm^2

Factor the left side:

x(x - 5/2) = 28 cm^2

Divide both sides by (x - 5/2):

x = 28 cm^2 / (x - 5/2)

Since we know that x is the length of the rectangle, and the length is 2 cm more than x, we can substitute x + 2 for x:

x + 2 = 28 cm^2 / (x + 2 - 5/2)

Simplify the right side:

x + 2 = 28 cm^2 / (x + 1)

Multiply both sides by (x + 1):

x + 2 = 28 cm^2

Subtract 2 from both sides:

x = 26 cm^2

Therefore, the length of the rectangle is 26 cm, and the width is 5 cm less than twice x, or 5 cm less than 52 cm, or 47 cm.

The answer is x = 26 cm.

answered
User WritingForAnroid
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7.9k points

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