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How many kilograms of steel comprised of 6 % nickel needs to be mixed with steel comprised of 14 % nickel

to produce 2000 kg of steel comprised of 8 % nickel?

asked
User Graywh
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1 Answer

6 votes

Let x be the amount of steel comprised of 6% nickel needed to be mixed with steel comprised of 14% nickel. Then, the amount of steel comprised of 14% nickel needed to produce 2000 kg of steel comprised of 8% nickel is 2000 - x.

To find the amount of nickel in each steel mixture, we multiply the amount of steel by its respective percentage of nickel, then add them together. The equation based on the amount of nickel is:

0.06x + 0.14(2000 - x) = 0.08(2000)

Simplifying and solving for x, we get:

0.06x + 280 - 0.14x = 160

-0.08x = -120

x = 1500

Therefore, 1500 kg of steel comprised of 6% nickel needs to be mixed with 500 kg of steel comprised of 14% nickel to produce 2000 kg of steel comprised of 8% nickel.

answered
User Wmute
by
8.4k points
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