Question

Jar A contains the 8 letters in the word Colorado. Jar B contains the 11 letters in the word Connecticut. What is the probability of randomly drawing an n from jar b and then drawing a t from jar b without replacing the n

Answer 1

Explanation:

The probability of drawing an "n" from Jar B is 2/11, since there are two "n"s out of a total of 11 letters. Once we draw an "n", there are 10 letters left in the jar, including one "t". Since we're not replacing the "n" that we drew, the probability of drawing a "t" next is 1/10.

Therefore, the probability of drawing an "n" from Jar B and then drawing a "t" without replacement is:

(2/11) * (1/10) = 2/110 = 1/55

So the probability is 1/55.