Question

In ΔOPQ, q = 590 cm, m m∠P=152° and m m∠Q=26°. Find the length of p, to the nearest centimeter.

Answer 1

p = 632cm

Explanation:

Since this triangle is not a right triangle we can't use right triangle trig...but, we can use the Law of Sines. We know both Angle Q and side q, so we can set up a ratio:

590/sin 26°

This would be equal to another ratio of side/sin Angle

p/sin152°

Write a proportion (equation) and solve.

590/sin26° = p/sin152°

see image.