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3 votes
Y=20x+0 what is the practice time for 300 strike outs x= practice time y=strike outs​

asked
User Stacy
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7.5k points

1 Answer

2 votes

The given equation is in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept. In this case, the slope is 20 and the y-intercept is 0.

The equation relates practice time (x) to the number of strike outs (y), where the number of strike outs (y) is equal to 20 times the practice time (x).

To find the practice time (x) for 300 strike outs (y), we can substitute y = 300 into the equation and solve for x:

y = 20x + 0

300 = 20x

x = 300/20

x = 15

Therefore, the practice time required for 300 strike outs is 15 units of time (which could be minutes, hours, or any other unit of time depending on the context).

answered
User MartinGrotzke
by
8.2k points
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