asked 202k views
2 votes
Find the zeros of 2x^3+px^2+qx+18

1 Answer

2 votes

Answer:

p = 29 and q = -3.

Explanation:

Using long division, the remainder when we divide by x − 1 is p+q−16. The remainder when we divide by x + 1 is p−q−20.

answered
User Tsurantino
by
9.0k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.