Question

In the reaction 2H2 + O2 → __H2O, what coefficient should be placed in front of H2O to balance the reaction?

1
2
3
4

Answer 1

Below

Step-by-step explanation:

2 H2 + O2 ====> H20 you have 4 H's on L...need 4 on right so:

2H2 + O2 =====> 2 H2 O Now H's are 'balanced' and a check of the O's shows they are balanced too (two O's on each side)