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Determine algebraically the co-ordinate of the points of intersection of the graphs of x-y=3 and xy=28​

asked
User Biozinc
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8.5k points

1 Answer

3 votes

Answer:

Explanation:

First write X - Y = 3 as X = 3 +Y.

Then, replace the value of X in the equation XY = 28.

That is, (3 + Y)Y = 28.

Then, we have
Y^(2) +3Y-28=0. By solving for Y, we have

Y = 4 and Y = -7. Then, replecing Y in the equation X - Y = 3. We have,

X = 7 and X = -4.

Hence, the points of interseccion are, (7,4) and (-4,7)

answered
User Tonisha
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7.6k points

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