Question

9 sec x + 9 tan x = 9

Answer 1

Lowest root is 0 degrees.

Explanation:

divide through by 9:

sec x + tan x = 1

sec^2x = 1 + tan^2 x so

√(1 + tan^2x) + tanx = 1

√(1 + tan^2x) = 1 - tanx

Squaring both sides:

1 + tan^2 x = 1 - 2 tanx + tan^2 x

1 = 1 - 2 tan x

2tanx = 0

x = 0 degree.