Question

A simple circuit contains a 20 V battery connected with wires to a small bulb. If the resistance of that bulb is 500 ohms, how much power is dissipated by the bulb? Group of answer choices 25 W 1,000 W 0.4 W 0.8 W

Answer 1

0.8 W

To solve this question, we can use the formula P = V^2/R, where P is power, V is voltage, and R is resistance. In this case, P = (20 V)^2/ 500 ohms = 0.8 W. Thus, the answer is 0.8 W.