Question

For the reactions system, 2H₂(g) + S₂(g) → 2H₂S(g), a 1.00 liter vessel is found to contain 0.5 moles of H₂, 0.02 moles of

S₂, and 68.5 moles of H₂S. What is the equilibrium constant expression?
O [H₂][S₂]
[H₂S]
O [H₂S]
[H₂] [S₂]
[H₂S]2
[H₂[S₂]
O [H₂²[S₂]
[H₂S]²

Answer 1

Step-by-step explanation:

The equilibrium constant expression for the reaction system is given by:

Kc = [H₂S]² / ([H₂]²[S₂])

Using the given molar amounts, we can calculate the equilibrium concentrations of each species:

[H₂] = 0.5 mol / 1 L = 0.5 M

[S₂] = 0.02 mol / 1 L = 0.02 M

[H₂S] = 68.5 mol / 1 L = 68.5 M

Substituting these values into the equilibrium constant expression, we get:

Kc = (68.5)² / ((0.5)²(0.02))

Kc = 19658.75

Therefore, the equilibrium constant expression for the given reaction system is [H₂S]² / ([H₂]²[S₂]), and its numerical value is approximately 19658.75. Note that the units of Kc depend on the units of concentration used for each species.