Answer:To determine the amount of water that can be produced from the reaction of 2.5 moles of H₂ and 4.5 moles of O₂, we first need to determine the limiting reagent. The limiting reagent is the reactant that runs out first and limits the amount of product that can be formed. In this reaction, the limiting reagent would be the reactant with the lowest stoichiometric ratio to the product, in this case, O₂.
Since 4.5 moles of O₂ is present, and the reaction requires 2 moles of O₂ for every 2 moles of H₂, only 2.5 moles of water can be produced. This means that 2.5 moles of H₂ is the limiting reagent, and the 4.5 moles of O₂ is the excess reagent.
In this reaction, 2.5 moles of water can be produced from the reaction of 2.5 moles of H₂ and 4.5 moles of O₂.
Step-by-step explanation: