Question

A bag contains three blue counters and four yellow counters. Two counters are removed without replacement and X is the number of blue counters removed.

Answer 1

This is a probability problem. To find the probability of removing two blue counters, we need to calculate the number of possible outcomes of removing two blue counters out of seven counters (3 blue and 4 yellow).

The number of possible outcomes of removing two blue counters is 3C2 = 3! / (2! * (3-2)!) = 3.

So, the probability of removing two blue counters is 3/7C2 = 3/21.

To find the probability of X being equal to 2, we need to calculate the probability of removing two blue counters.

Therefore, the probability of X being equal to 2 is 3/21.