Answer:
Step-by-step explanation:
The balanced equation for the reaction between lead (Pb) and copper (II) sulfate (CuSO4) is:
Pb + CuSO4 -> PbSO4 + Cu
In this equation, one mole of lead reacts with one mole of copper (II) sulfate to produce one mole of lead sulfate and one mole of copper. This equation represents a redox reaction, where lead acts as the reducing agent and copper (II) sulfate acts as the oxidizing agent. The transfer of electrons from lead to copper (II) sulfate results in the formation of lead sulfate and copper.