Question

4x^-3 y^-2 for x = 2 and y = 1? Pls Show work

Answer 1

To substitute x = 2 and y = 1 into the expression 4x^-3 y^-2, we simply replace x with 2 and y with 1:

4 * (2)^-3 * (1)^-2 = 4 * (1/8) * (1) = 4/8 = 0.5

So the expression 4x^-3 y^-2 evaluated at x = 2 and y = 1 is equal to 0.5.

Explanation: