Question

Differentiate: y = 2 + ln(3-2x)

Answer 1

To differentiate y = 2 + ln(3 - 2x), we use the logarithmic differentiation rule, which states that if y = ln(u), then dy/dx = du/dx / u.

Starting with y = 2 + ln(3 - 2x), we write u = 3 - 2x and differentiate:

du/dx = -2
dy/dx = -2 / (3 - 2x)

So, the derivative of y = 2 + ln(3 - 2x) with respect to x is:

dy/dx = -2 / (3 - 2x)