Question

Solving right triangle

Answer 1

`BC= 2.23`

Explanation:

We can solve this problem using the trigonometric identity of
`sin`.

We know:

`sin(\theta) = (opposite)/(hypotenuse)\\\\sin(50 \textdegree) = (?)/(3)\\`

If we solve for
`?` we get:

`3sin(50 \textdegree) \approx 2.23`