Question

Sodium chlorate decomposes into sodium chloride and oxygen gas as seen in the equation below.

­­2NaClO3­ --> 2NaCl +3O2

How many moles of NaClO3­ were needed to produce 30 moles of O2? Round your answer to the nearest whole number.

Answer 1

10 moles of NaClO3 were needed to produce 30 moles of O2

Step-by-step explanation:

From the equation, we know that 2 moles of NaClO3 produce 3 moles of O2. To find out how many moles of NaClO3 are needed to produce 30 moles of O2, we divide the number of moles of O2 by the mole ratio:

30 moles O2 / 3 moles O2 per 2 moles NaClO3 = 10 moles NaClO3

So, 10 moles of NaClO3 were needed to produce 30 moles of O2.