asked 97.2k views
3 votes
What is the minimum value of y=x^2+36/5

asked
User IMOBAMA
by
7.9k points

1 Answer

4 votes

Answer:

(36/5)

Explanation:

y=x^2+36/5

Since x is squared, the result will always be a positive number, regardless of the actual value of x. Starting with a value of x of zero, the x^2 term will only grow as one moves away from 0. E.g., (-1)^2 = 1, (-2)^2 = 4, etc.

So the minium for this equation will occur when x = 0. It only gets larger from that point. The minimum is (36/5).

See the attached graph.

What is the minimum value of y=x^2+36/5-example-1
answered
User Muhasturk
by
8.3k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.